About Huazhou
Huazhou is a large city located in People's Republic of China, in the Guangdong region. According to the latest available data (2026), the population of Huazhou is approximately 1,291,668 residents, making it the #362 most populous city in People's Republic of China.
Globally, Huazhou ranks #1,350 among the world's most populated cities. With over 1 million residents, Huazhou plays an important role as an economic and cultural center in People's Republic of China.
Huazhou City Statistics
| City | Huazhou |
| Country | |
| Population | 1,291,668 |
| Global Rank | #1,350 |
| Rank in People's Republic of China | #362 of 2,667 cities |
| City Category | large city |
| Region | Guangdong |
| Latitude | 21.6333 |
| Longitude | 110.5833 |
| Data Year | 2026 |
Population Comparison
To put Huazhou's population of 1,291,668 into perspective:
- Huazhou has approximately 1.3 million residents.
- This makes it comparable in size to cities like Prague or Munich.
Where is Huazhou
Located?
Huazhou is located in People's Republic of China, in the Guangdong region, at coordinates 21.6333° latitude and 110.5833° longitude. Located near the equator, Huazhou experiences a tropical climate with warm temperatures throughout the year.
Nearby Cities
Other Cities in People's Republic of China
Largest Cities in People's Republic of China
| # | City | Population |
|---|---|---|
| 1 | Kaifeng | 4,824,016 |
| 2 | Yuncheng | 4,774,508 |
| 3 | Chenzhou | 4,667,134 |
| 4 | Yibin | 4,588,804 |
| 5 | Huai'an | 4,556,230 |
Frequently Asked Questions
What is the population of Huazhou?
The population of Huazhou is approximately 1,291,668 residents according to the latest available data (2026).
Where is Huazhou located?
Huazhou is located in People's Republic of China at approximately 21.6333° latitude and 110.5833° longitude.
Is Huazhou one of the largest cities in People's Republic of China?
With a population of 1,291,668, Huazhou is one of the major urban areas in People's Republic of China. It ranks #362 out of 2,667 cities in the country.