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Population of East Flatbush, United States US flag

City with 178,464 residents in New York, United States.

178,464
Residents (2026)
#9,732
World Ranking
#452
In United States (of 867)

About East Flatbush

East Flatbush is a city located in United States, in the New York region. According to the latest available data (2026), the population of East Flatbush is approximately 178,464 residents, making it the #452 most populous city in United States.

Globally, East Flatbush ranks #9,732 among the world's most populated cities.

East Flatbush City Statistics

CityEast Flatbush
CountryUS flag United States
Population178,464
Global Rank#9,732
Rank in United States#452 of 867 cities
City Categorycity
RegionNew York
Latitude40.6438
Longitude-73.93
Data Year2026

Where is East Flatbush US flag Located?

East Flatbush is located in United States, in the New York region, at coordinates 40.6438° latitude and -73.93° longitude. Located in the mid-latitudes, East Flatbush experiences distinct four-season weather patterns.

Nearby Cities

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# City Population
1 Harris County 4,731,145
2 Los Angeles 3,898,747
3 San Diego County 3,298,634
4 Brooklyn 2,736,074
5 Miami-Dade County 2,701,767

Frequently Asked Questions

What is the population of East Flatbush?

The population of East Flatbush is approximately 178,464 residents according to the latest available data (2026).

Where is East Flatbush located?

East Flatbush is located in United States at approximately 40.6438° latitude and -73.93° longitude.

Is East Flatbush one of the largest cities in United States?

With a population of 178,464, East Flatbush is one of the notable urban areas in United States. It ranks #452 out of 867 cities in the country.

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