About Bargarh district
Bargarh district is a large city located in India, in the Odisha region. According to the latest available data (2026), the population of Bargarh district is approximately 1,481,255 residents, making it the #373 most populous city in India.
Globally, Bargarh district ranks #1,166 among the world's most populated cities. With over 1 million residents, Bargarh district plays an important role as an economic and cultural center in India.
Bargarh district City Statistics
| City | Bargarh district |
| Country |  India |
| Population | 1,481,255 |
| Global Rank | #1,166 |
| Rank in India | #373 of 1,225 cities |
| City Category | large city |
| Region | Odisha |
| Latitude | 21.3333 |
| Longitude | 83.6167 |
| Data Year | 2026 |
Population Comparison
To put Bargarh district's population of 1,481,255 into perspective:
- Bargarh district has approximately 1.5 million residents.
- This makes it comparable in size to cities like Prague or Munich.
Where is Bargarh district Located?
Bargarh district is located in India, in the Odisha region, at coordinates 21.3333° latitude and 83.6167° longitude. Located near the equator, Bargarh district experiences a tropical climate with warm temperatures throughout the year.
Nearby Cities
Other Cities in India
Largest Cities in India
| # | City | Population |
|---|---|---|
| 1 | Muzaffarpur district | 4,801,062 |
| 2 | Belagavi district | 4,779,661 |
| 3 | Moradabad district | 4,772,006 |
| 4 | Ghaziabad district | 4,681,645 |
| 5 | Nagpur division | 4,653,570 |
Frequently Asked Questions
What is the population of Bargarh district?
The population of Bargarh district is approximately 1,481,255 residents according to the latest available data (2026).
Where is Bargarh district located?
Bargarh district is located in India at approximately 21.3333° latitude and 83.6167° longitude.
Is Bargarh district one of the largest cities in India?
With a population of 1,481,255, Bargarh district is one of the major urban areas in India. It ranks #373 out of 1,225 cities in the country.
